Java Integer - parseInt() Method

The java.lang.Integer.parseInt() method is used to parse the string argument as a signed decimal integer. The characters in the string must all be decimal digits, except that the first character may be an ASCII minus sign '-' ('\u002D') to indicate a negative value or an ASCII plus sign '+' ('\u002B') to indicate a positive value. The resulting integer value is returned, exactly as if the argument and the radix 10 were given as arguments to the parseInt(java.lang.String, int) method.

Syntax

public static int parseInt(String s)
                    throws NumberFormatException

Parameters

Return Value

Returns the integer value represented by the argument in decimal.

Exception

Throws NumberFormatException, if the string does not contain a parsable integer.

Example:

In the example below, the java.lang.Integer.parseInt() method is used to parse the string argument as a signed decimal integer.

import java.lang.*;

public class MyClass {
  public static void main(String[] args) {
    
    //creating a string holding int value
    String x = "25";

    //creating int value
    int y = Integer.parseInt(x);

    //printing the string
    System.out.println("The string is: " + x); 

    //printing the int value
    System.out.println("The int value is: " + y);   
  }
}

The output of the above code will be:

The string is: 25
The int value is: 25