C++ - Returning an array from a function
An array of pointers is defined as the same way as an array. The declaration starts with datatype pointed to by the pointer followed by * and name of the array of pointers with size enclosed in square brackets. Please see the syntax below:
Syntax
//integer datatype array of pointer //with name p and size 5. int *p[5];
Example:
In the below example, an array called MyArray and array of pointers called p are created. p is assigned the address of MyArray using address-of (&) operator to create array of pointers.
#include <iostream>
using namespace std;
int main (){
int MyArray[5] = {100, 200, 300, 400, 500};
int *p[5];
for(int i = 0; i<5; i++)
{
p[i] = &MyArray[i];
}
for(int i = 0; i<5; i++)
{
cout<<*p[i]<<"\n";
}
return 0;
}
The output of the above code will be:
100 200 300 400 500
Example:
An array of pointers to character can also be used to store a list of strings. Please see the example below:
#include <iostream>
using namespace std;
int main (){
const char *p[5] = {"Blue", "Red", "Green"};
//see memory location
for(int i = 0; i<3; i++)
{
cout<<p+i<<"\n";
}
//see value stored
for(int i = 0; i<3; i++)
{
cout<<*(p+i)<<"\n";
}
return 0;
}
The output of the above code will be:
0x7ffd023e3f50 0x7ffd023e3f58 0x7ffd023e3f60 Blue Red Green
