Java Math - E Field
The Java E field is used to return the value of e to the available precision. It returns the value of e as 2.718281828459045.
Syntax
public const double E = 2.718281828459045;
Parameters
No parameter is required.
Return Value
Returns the value of e to the available precision.
Example:
In the example below, Math.E constant is used to return the value of e to the available precision.
public class MyClass { public static void main(String[] args) { double const_e = Math.E; System.out.println("Math.E = " + const_e); System.out.println("Math.log(Math.E) = " + Math.log(const_e)); System.out.println("Math.log10(Math.E) = " + Math.log10(const_e)); } }
The output of the above code will be:
Math.E = 2.718281828459045 Math.log(Math.E) = 1.0 Math.log10(Math.E) = 0.4342944819032518
❮ Java Math Methods