# C# Math - Truncate() Function

The C# Truncate() method is used to round the given number towards zero. It returns the nearest integral value with absolute value less than the argument. In special cases it returns the following:

• If the argument is NaN, the method returns NaN.
• If the argument is positive infinity or negative infinity, the method returns same as the argument.

### Syntax

```public static decimal Truncate (decimal x);
```

### Parameters

 `x` Specify a number.

### Return Value

Returns the nearest integral value with absolute value less than the argument.

### Example:

In the example below, Truncate() function returns the nearest integral value with absolute value less than the argument.

```using System;

class MyProgram {
static void Main(string[] args) {
Console.WriteLine("Math.Truncate(2.5) = "
+ Math.Truncate(2.5));
Console.WriteLine("Math.Truncate(5.78) = "
+ Math.Truncate(5.78));
Console.WriteLine("Math.Truncate(-3.5) = "
+ Math.Truncate(-3.5));
Console.WriteLine("Math.Truncate(-10.33) = "
+ Math.Truncate(-10.33));
Console.WriteLine("Math.Truncate(Double.NaN) = "
+ Math.Truncate(Double.NaN));
Console.WriteLine("Math.Truncate(Double.NegativeInfinity) = "
+ Math.Truncate(Double.NegativeInfinity));
Console.WriteLine("Math.Truncate(Double.PositiveInfinity) = "
+ Math.Truncate(Double.PositiveInfinity));
}
}
```

The output of the above code will be:

```Math.Truncate(2.5) = 2
Math.Truncate(5.78) = 5
Math.Truncate(-3.5) = -3
Math.Truncate(-10.33) = -10
Math.Truncate(Double.NaN) = NaN
Math.Truncate(Double.NegativeInfinity) = -Infinity
Math.Truncate(Double.PositiveInfinity) = Infinity
```

❮ C# Math Methods

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