Java Random - nextInt() Method
The java.util.Random.nextInt() method returns the next pseudorandom, uniformly distributed int value from this random number generator's sequence.
Syntax
public int nextInt()
Parameters
No parameter is required.
Return Value
Returns the next pseudorandom, uniformly distributed int value from this random number generator's sequence.
Exception
NA
Example:
In the example below, the java.util.Random.nextInt() method is used to get pseudorandom number, uniformly distributed int value.
import java.util.*;
public class MyClass {
public static void main(String[] args) {
//creating a random object
Random rand = new Random();
//printing uniformly distributed int random numbers
for(int i = 0; i < 5; i++)
System.out.println("Next Int Value: " + rand.nextInt());
}
}
One of the possible outcome is given below:
Next Int Value: -516357581 Next Int Value: 240187520 Next Int Value: 436141256 Next Int Value: -1813115768 Next Int Value: -450772196
❮ Java.util - Random
