# Scala - Math log1p() Method

The Scala Math log1p() method returns the natural logarithm of (1 + number), i.e., log(1+number). In special cases it returns the following:

• If the argument is NaN or less than -1, then the result is NaN.
• If the argument is positive infinity, then the result is positive infinity.
• If the argument is negative one, then the result is negative infinity.

### Syntax

```def log1p(x: Double): Double = java.lang.Math.log1p(x)
```

### Parameters

 `x` Specify the number.

### Return Value

Returns the natural logarithm of (1 + number), i.e., log(1+number).

NA.

### Example:

In the example below, log1p() method is used to calculate the log(1+number).

```import scala.math._

object MainObject {
def main(args: Array[String]) {
println(s"log1p(E) = \${log1p(E)}");
println(s"log1p(E - 1) = \${log1p(E - 1)}");
println(s"log1p(50) = \${log1p(50)}");
println(s"log1p(-1) = \${log1p(-1)}");
println(s"log1p(Double.NaN) = \${log1p(Double.NaN)}");
println("log1p(Double.PositiveInfinity) = "
+ log1p(Double.PositiveInfinity));
println("log1p(Double.NegativeInfinity) = "
+ log1p(Double.NegativeInfinity));
}
}
```

The output of the above code will be:

```log1p(E) = 1.3132616875182228
log1p(E - 1) = 1.0
log1p(50) = 3.9318256327243257
log1p(-1) = -Infinity
log1p(Double.NaN) = NaN
log1p(Double.PositiveInfinity) = Infinity
log1p(Double.NegativeInfinity) = NaN
```

❮ Scala - Math Methods

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