C# Data Structures - Circular Doubly Linked List Other Related Topics

C# - Circular Doubly Linked List



A circular doubly linked list is a linear data structure, in which the elements are stored in the form of a node. Each node contains three sub-elements. A data part that stores the value of the element, the previous part that stores the link to the previous node, and the next part that stores the link to the next node as shown in the below image:

Linked List Node

The first node also known as HEAD is always used as a reference to traverse the list. Last element contains link to the first element as next and the first element contains link of the last element as previous. A circular doubly linked can be visualized as a chain of nodes, where every node points to previous and next node.

Linked List

Implementation of Circular Doubly Linked List

Representation:

In C#, circular doubly linked list can be represented as a class and a Node as a separate class. The LinkedList class contains a reference of Node class type.

//node structure
class Node {
  public int data;
  public Node next;
  public Node prev;
};

class LinkedList {
  public Node head;
  //constructor to create an empty LinkedList
  public LinkedList(){
    head = null;
  }  
};

Create a Circular Doubly Linked List

Let us create a simple circular doubly linked list which contains three data nodes.

using System;

//node structure
class Node {
  public int data;
  public Node next;
  public Node prev;
};

class LinkedList {
  public Node head;
  //constructor to create an empty LinkedList
  public LinkedList(){
    head = null;
  }   
};

// test the code 
class Implementation { 
  static void Main(string[] args) {
    //create an empty LinkedList 
    LinkedList MyList = new LinkedList();

    //Add first node.
    Node first = new Node();
    first.data = 10;
    first.next = null; 
    first.prev = null; 
    //linking with head node
    MyList.head = first;
    //linking next of the node with head
    first.next = MyList.head;
    //linking prev of the head 
    MyList.head.prev = first;

    //Add second node.
    Node second = new Node();
    second.data = 20;
    second.next = null; 
    //linking with first node
    second.prev = first;
    first.next = second;
    //linking next of the node with head
    second.next = MyList.head;
    //linking prev of the head 
    MyList.head.prev = second;

    //Add third node.
    Node third = new Node();
    third.data = 30;
    third.next = null; 
    //linking with second node
    third.prev = second;
    second.next = third;
    //linking next of the node with head
    third.next = MyList.head;
    //linking prev of the head 
    MyList.head.prev = third; 
  }
}

Traverse a Circular Doubly Linked List

A circular doubly linked list can be traversed from any node of the list using a temp node. Keep on moving the temp node to the next one and displaying its content. Stop the traversal, after reaching the starting node.

using System;

//node structure
class Node {
  public int data;
  public Node next;
  public Node prev;
};

class LinkedList {
  public Node head;
  //constructor to create an empty LinkedList
  public LinkedList(){
    head = null;
  } 

  //display the content of the list
  public void PrintList() {
    Node temp = new Node();
    temp = this.head;
    if(temp != null) {
      Console.Write("The list contains: ");
      while(true) {
        Console.Write(temp.data + " ");
        temp = temp.next;
        if(temp == this.head)
          break;        
      }
      Console.WriteLine();
    } else {
      Console.WriteLine("The list is empty.");
    }
  }      
};

// test the code 
class Implementation { 
  static void Main(string[] args) {
    //create an empty LinkedList 
    LinkedList MyList = new LinkedList();

    //Add first node.
    Node first = new Node();
    first.data = 10;
    first.next = null; 
    first.prev = null; 
    //linking with head node
    MyList.head = first;
    //linking next of the node with head
    first.next = MyList.head;
    //linking prev of the head 
    MyList.head.prev = first;

    //Add second node.
    Node second = new Node();
    second.data = 20;
    second.next = null; 
    //linking with first node
    second.prev = first;
    first.next = second;
    //linking next of the node with head
    second.next = MyList.head;
    //linking prev of the head 
    MyList.head.prev = second;

    //Add third node.
    Node third = new Node();
    third.data = 30;
    third.next = null; 
    //linking with second node
    third.prev = second;
    second.next = third;
    //linking next of the node with head
    third.next = MyList.head;
    //linking prev of the head 
    MyList.head.prev = third; 

    //print the content of list
    MyList.PrintList();     
  }
}

The above code will give the following output:

The list contains: 10 20 30