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The SQL RIGHT OUTER JOIN keyword is same as SQL RIGHT JOIN keyword and it is used to combine column values of two tables based on the match between the columns. It returns all rows of the table on the right side of the join and matching rows of the table on the left side of the join. The rows of the right side table where there is no match in the left side table, the result table will contain NULL value.

Syntax

The syntax for using RIGHT JOIN keyword is given below:

SELECT table1.column1, table1.column2, table2.column1, table2.column2, ...
FROM table1
RIGHT OUTER JOIN table2
ON table1.matching_column = table2.matching_column;

Example:

Consider a database tables called Employee and Contact_Info with the following records:

Table 1: Employee table

EmpIDNameAgeSalary
1John253000
2Marry242750
3Jo272800
4Kim303100
5Ramesh283000
6Huang282800

Table 2: Contact_Info table

Phone_NumberEmpIDAddress
+1-80XXXXX0002XXX, Brooklyn, New York, USA
+33-14XXXXX013XXX, Grenelle, Paris, France
+31-20XXXXX194XXX, Geuzenveld, Amsterdam, Netherlands
+86-10XXXXX4586XXX, Yizhuangzhen, Beijing, China
+65-67XXXXX47XXX, Yishun, Singapore
+81-35XXXXX728XXX, Koto City, Tokyo, Japan

  • To right outer join Employee and Contact_Info tables based on matching column EmpID, the SQL code is given below. This will fetch Name and Age columns from Employee table and Address column from Contact_Info table.

    SELECT Employee.Name, Employee.Age, Contact_Info.Address 
    FROM Employee
    RIGHT OUTER JOIN Contact_Info
    ON Employee.EmpID = Contact_Info.EmpID;
    

    This will produce the result as shown below:

    NameAgeAddress
    Marry24XXX, Brooklyn, New York, USA
    Jo27XXX, Grenelle, Paris, France
    Kim30XXX, Geuzenveld, Amsterdam, Netherlands
    Huang28XXX, Yizhuangzhen, Beijing, China
    NULLNULLXXX, Yishun, Singapore
    NULLNULLXXX, Koto City, Tokyo, Japan
  • To fetch all fields of a table, table.* keyword is used, for example - to fetch all fields of the Employee table, Employee.* is used in the below SQL code:

    SELECT Employee.*, Contact_Info.Address 
    FROM Employee
    RIGHT OUTER JOIN Contact_Info
    ON Employee.EmpID = Contact_Info.EmpID;
    

    This result of the following code will be:

    EmpIDNameAgeSalaryAddress
    2Marry242750XXX, Brooklyn, New York, USA
    3Jo272800XXX, Grenelle, Paris, France
    4Kim303100XXX, Geuzenveld, Amsterdam, Netherlands
    6Huang282800XXX, Yizhuangzhen, Beijing, China
    NULLNULLNULLNULLXXX, Yishun, Singapore
    NULLNULLNULLNULLXXX, Koto City, Tokyo, Japan