# C# Math - BitIncrement() Method

The C# BitIncrement() method returns the next largest value that compares greater than the argument. In special cases it returns the following:

• If the argument is NaN, the method returns NaN.
• If the argument is positive infinity, the method returns positive infinity.

### Syntax

```public static double BitIncrement (double arg);
```

### Parameters

 `arg` Specify the value to increment.

### Return Value

Returns the next largest value that compares greater than the argument.

### Example:

In the example below, BitIncrement() method returns the next largest value that compares greater than the argument.

```using System;

class MyProgram {
static void Main(string[] args) {
Console.WriteLine("Math.BitIncrement(2) = "
+ Math.BitIncrement(2));
Console.WriteLine("Math.BitIncrement(10.1) = "
+ Math.BitIncrement(10.1));
Console.WriteLine("Math.BitIncrement(32.23) = "
+ Math.BitIncrement(32.23));
Console.WriteLine("Math.BitIncrement(0) = "
+ Math.BitIncrement(0));
Console.WriteLine("Math.BitIncrement(-10.1) = "
+ Math.BitIncrement(-10.1));
Console.WriteLine("Math.BitIncrement(Double.NaN) = "
+ Math.BitIncrement(Double.NaN));
Console.WriteLine("Math.BitIncrement(Double.NegativeInfinity) = "
+ Math.BitIncrement(Double.NegativeInfinity));
Console.WriteLine("Math.BitIncrement(Double.PositiveInfinity) = "
+ Math.BitIncrement(Double.PositiveInfinity));
}
}
```

The output of the above code will be:

```Math.BitIncrement(2) = 2.0000000000000004
Math.BitIncrement(10.1) = 10.100000000000001
Math.BitIncrement(32.23) = 32.230000000000004
Math.BitIncrement(0) = 5E-324
Math.BitIncrement(-10.1) = -10.099999999999998
Math.BitIncrement(Double.NaN) = NaN
Math.BitIncrement(Double.NegativeInfinity) = -1.7976931348623157E+308
Math.BitIncrement(Double.PositiveInfinity) = Infinity
```

❮ C# Math Methods

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