C# Math - BitIncrement() Method

The C# BitIncrement() method returns the next largest value that compares greater than the argument. In special cases it returns the following:

If the argument is NaN, the method returns NaN.
If the argument is positive infinity, the method returns positive infinity.

Syntax

public static double BitIncrement (double arg);

Parameters

arg Specify the value to increment.

Return Value

Returns the next largest value that compares greater than the argument.

Example:

In the example below, BitIncrement() method returns the next largest value that compares greater than the argument.

using System;

class MyProgram {
  static void Main(string[] args) {
    Console.WriteLine("Math.BitIncrement(2) = "
                      + Math.BitIncrement(2));
    Console.WriteLine("Math.BitIncrement(10.1) = "
                      + Math.BitIncrement(10.1));
    Console.WriteLine("Math.BitIncrement(32.23) = "
                      + Math.BitIncrement(32.23));                      
    Console.WriteLine("Math.BitIncrement(0) = "
                      + Math.BitIncrement(0));
    Console.WriteLine("Math.BitIncrement(-10.1) = "
                      + Math.BitIncrement(-10.1));
    Console.WriteLine("Math.BitIncrement(Double.NaN) = "
                      + Math.BitIncrement(Double.NaN));
    Console.WriteLine("Math.BitIncrement(Double.NegativeInfinity) = "
                      + Math.BitIncrement(Double.NegativeInfinity));
    Console.WriteLine("Math.BitIncrement(Double.PositiveInfinity) = "
                      + Math.BitIncrement(Double.PositiveInfinity));
  }
}

The output of the above code will be:

Math.BitIncrement(2) = 2.0000000000000004
Math.BitIncrement(10.1) = 10.100000000000001
Math.BitIncrement(32.23) = 32.230000000000004
Math.BitIncrement(0) = 5E-324
Math.BitIncrement(-10.1) = -10.099999999999998
Math.BitIncrement(Double.NaN) = NaN
Math.BitIncrement(Double.NegativeInfinity) = -1.7976931348623157E+308
Math.BitIncrement(Double.PositiveInfinity) = Infinity

❮ C# Math Methods