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C# Math - E Field



The C# E field is used to return the value of e to the available precision. It returns the value of e as 2.7182818284590451.

Syntax

public const double E = 2.7182818284590451;

Parameters

No parameter is required.

Return Value

Returns the value of e to the available precision.

Example:

In the example below, Math.E constant is used to return the value of e to the available precision.

using System;

class MyProgram {
  static void Main(string[] args) {
    double e = Math.E;
    Console.WriteLine("Math.E = " + e);
    Console.WriteLine("Math.Log(Math.E) = " + Math.Log(e));
    Console.WriteLine("Math.Log10(Math.E) = " + Math.Log10(e));
  }
}

The output of the above code will be:

Math.E = 2.71828182845905
Math.Log(Math.E) = 1
Math.Log10(Math.E) = 0.434294481903252

❮ C# Math Methods

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