C# Math - Sqrt() Method

The C# Sqrt() method returns the square root of the given number. In special cases it returns the following:

If the argument is NaN or less than zero, then method returns NaN.
If the argument is positive infinity, the method returns the same as the argument.

Syntax

public static float Sqrt (float arg);

Parameters

arg Specify the number whose square root to be found.

Return Value

Returns the square root of the specified number.

Example:

In the example below, Sqrt() method is used to find out the square root of the given number.

using System;

class MyProgram {
  static void Main(string[] args) {
    Console.WriteLine("Math.Sqrt(64) = "
                      + Math.Sqrt(64));
    Console.WriteLine("Math.Sqrt(500) = "
                      + Math.Sqrt(500));
    Console.WriteLine("Math.Sqrt(-500) = "
                      + Math.Sqrt(-500));
    Console.WriteLine("Math.Sqrt(Double.NaN) = "
                      + Math.Sqrt(Double.NaN));
    Console.WriteLine("Math.Sqrt(Double.NegativeInfinity) = "
                      + Math.Sqrt(Double.NegativeInfinity));
    Console.WriteLine("Math.Sqrt(Double.PositiveInfinity) = "
                      + Math.Sqrt(Double.PositiveInfinity));
  }
}

The output of the above code will be:

Math.Sqrt(64) = 8
Math.Sqrt(500) = 22.3606797749979
Math.Sqrt(-500) = NaN
Math.Sqrt(Double.NaN) = NaN
Math.Sqrt(Double.NegativeInfinity) = NaN
Math.Sqrt(Double.PositiveInfinity) = Infinity

❮ C# Math Methods