C# - right shift assignment operator

The Bitwise right shift assignment operator (>>=) assigns the first operand a value equal to the result of Bitwise right shift operation of two operands.

(x >>= y) is equivalent to (x = x >> y)

The Bitwise right shift operator (>>) takes the two numbers and right shift the bits of first operand by number of place specified by second operand. For example: for right shifting the bits of x by y places, the expression (x>>y) can be used. It is equivalent to dividing x by 2y.

The example below describes how right shift operator works:

1000 >> 2 returns 250

(In Binary)
1000         ->    1111101000
>> 2                     |  right shift the bits
-----                    V  by 2 places
250         <-      11111010
(In Binary)

The code of using right shift operator (>>) is given below:

using System;

class MyProgram {
static void Main(string[] args) {
int x = 1000;

//right shift assignment operation
x >>= 2;

//Displaying the result
Console.WriteLine("x = "+x);
}
}

The output of the above code will be:

x = 250

Example: Find largest power of 2 less than or equal to given number

Consider an integer 1000. In the bit-wise format, it can be written as 1111101000. However, all bits are not written here. A complete representation will be 32 bit representation as given below:

00000000000000000000001111101000

Performing N = N | (N>>i) operation, where i = 1, 2, 4, 8, 16 will change all right side bit to 1. When applied on 1000, the result in 32 bit representation is given below:

00000000000000000000001111111111

Adding one to this result and then right shifting the result by one place will give largest power of 2 less than or equal to 1000.

00000000000000000000001000000000

The below code will calculate the largest power of 2 less than or equal to given number.

using System;

class MyProgram {
static int MaxPowerOfTwo(int N) {
//changing all right side bits to 1.
N = N | (N>>1);
N = N | (N>>2);
N = N | (N>>4);
N = N | (N>>8);
N = N | (N>>16);

//adding 1 to N makes smallest power
//of 2 greater than given number
N = N + 1;

//right shift by one position makes
//largest power of 2 less than or
//equal to given number
N >>= 1;

return N;
}

static void Main(string[] args) {
Console.WriteLine("MaxPowerOfTwo(100) = "+
MaxPowerOfTwo(100));
Console.WriteLine("MaxPowerOfTwo(500) = "+
MaxPowerOfTwo(500));
Console.WriteLine("MaxPowerOfTwo(1000) = "+
MaxPowerOfTwo(1000));
}
}

The above code will give the following output:

MaxPowerOfTwo(100) = 64
MaxPowerOfTwo(500) = 256
MaxPowerOfTwo(1000) = 512

❮ C# - Operators

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