Swift - log1p() Function
The Swift log1p() function returns the natural logarithm of (1 + number), i.e., log(1+number).
Syntax
In Foundation framework, it is defined as follows:
public func log1p(_ x: CGFloat) -> CGFloat public func log1p(_ x: Float) -> Float public func log1p(_ x: Float80) -> Float80 public func log1p(_ __x: Double) -> Double
Parameters
x |
Specify the number. |
Return Value
Returns the natural logarithm of (1 + x), i.e., log(1+x).
If the x is less than -1, it returns -nan.
If the x is -1, it returns -inf.
Example:
In the example below, log1p() function is used to calculate the log(1+number).
import Foundation
print("log1p(-1.0) = \(log1p(-1.0))")
print("log1p(0.0) = \(log1p(0.0))")
print("log1p(10.0) = \(log1p(10.0))")
print("log1p(50.0) = \(log1p(50.0))")
print("log1p(-2.0) = \(log1p(-2.0))")
The output of the above code will be:
log1p(-1.0) = -inf log1p(0.0) = 0.0 log1p(10.0) = 2.3978952727983707 log1p(50.0) = 3.9318256327243257 log1p(-2.0) = -nan
❮ Swift Math Functions
