Three numbers $$x$$, $$y$$ and $$z$$ are given and the largest number among these three numbers can be found out using below methods.
In the below example, only if conditional statements are used.
#include <iostream>
using namespace std;
static void largest(int, int, int);
static void largest(int x, int y, int z) {
int max = x;
if (x >= y && x >= z)
{max = x;}
if (y >= x && y >= z)
{max = y;}
if (z >= x && z >= y)
{max = z;}
cout<<"largest number among "<<x<<", "<<y<<" and "<<z<<" is: "<<max<<"\n";
}
int main() {
largest(100, 50, 25);
largest(50, 50, 25);
return 0;
}
largest number among 100 , 50 and 25 is: 100 largest number among 50 , 50 and 25 is: 50
It can also be solved using If-else conditional statements.
#include <iostream>
using namespace std;
static void largest(int, int, int);
static void largest(int x, int y, int z) {
int max = x;
if (x >= y && x >= z)
{max = x;}
else if (y >= x && y >= z)
{max = y;}
else
{max = z;}
cout<<"largest number among "<<x<<", "<<y<<" and "<<z<<" is: "<<max<<"\n";
}
int main() {
largest(100, 50, 25);
largest(50, 50, 25);
return 0;
}
largest number among 100 , 50 and 25 is: 100 largest number among 50 , 50 and 25 is: 50
The above problem can also be solved using nested if-else conditional statements.
#include <iostream>
using namespace std;
static void largest(int, int, int);
static void largest(int x, int y, int z) {
int max = x;
if (x >= y)
{
if(x >= z)
{max = x;}
else
{max = z;}
}
else
{
if(y >= z)
{max = y;}
else
{max = z;}
}
cout<<"largest number among "<<x<<", "<<y<<" and "<<z<<" is: "<<max<<"\n";
}
int main() {
largest(100, 50, 25);
largest(50, 50, 25);
return 0;
}
largest number among 100 , 50 and 25 is: 100 largest number among 50 , 50 and 25 is: 50
The ternary operator can also be used here.
#include <iostream>
using namespace std;
static void largest(int, int, int);
static void largest(int x, int y, int z) {
int max = x;
max = (x > y)? ((x > z)? x : z) : ((y > z)? y : z);
cout<<"largest number among "<<x<<", "<<y<<" and "<<z<<" is: "<<max<<"\n";
}
int main() {
largest(100, 50, 25);
largest(50, 50, 25);
return 0;
}
largest number among 100 , 50 and 25 is: 100 largest number among 50 , 50 and 25 is: 50
