C++ Program to Check Leap Year
A leap year is a calendar year in which an additional day is added to February month. In a leap year, the number of days in February month and the year are 29 and 366 respectively. A year that is not a leap year is called a common year. A year is said to be a leap year if:
- it is divisible by 4.
- it is divisible by 4 but not divisible by 100.
- it is divisible by 4, 100 and 400.
Method 1: Using conditional statements
In the below example, conditional statements are used to identify a leap year.
#include <iostream> using namespace std; int main() { int year = 2019; if (year % 400 == 0) { cout<<year<<" is a leap year."; } else if (year % 100 == 0) { cout<<year<<" is not a leap year."; } else if (year % 4 == 0) { cout<<year<<" is a leap year."; } else { cout<<year<<" is not a leap year."; } return 0; }
The above code will give the following output:
2019 is not a leap year.
Method 2: Using function
In the below example, a function called leapyear() is created which takes year as argument and prints whether the passed year is a leap year or not.
#include <iostream> using namespace std; static void leapyear(int); static void leapyear(int year) { if (year % 400 == 0) { cout<<year<<" is a leap year."; } else if (year % 100 == 0) { cout<<year<<" is not a leap year."; } else if (year % 4 == 0) { cout<<year<<" is a leap year."; } else { cout<<year<<" is not a leap year."; } } int main() { leapyear(2019); return 0; }
The above code will give the following output:
2019 is not a leap year.