# Python - Set intersection() Method

The Python set intersection() method is used to return a set which contains all common elements of two or more sets. This method can take any number of sets or iterables to compute the intersection set. Please note that, this method does not change the original set.

The below figure depicts two sets called A = {10, 20, 30, 40, 50, 60} and B = {50, 60, 70, 80}. As 50 and 60 are common elements between A and B, hence intersection of these sets will be {50, 60}. The intersection() method can be expressed as:

• A.intersection(B) is same as AꓵB
• B.intersection(A) is same as BꓵA
• A.intersection(B, C) is same as AꓵBꓵC

### Syntax

set.intersection(iterable(s))


### Parameters

 iterable(s) Optional. specify set(s) or iterable(s) to compute intersection set.

### Example: Intersection set using set as an argument

In the below example, two sets called SetA and SetB are taken to compute intersection of these sets using python intersection() method.

SetA = {10, 20, 30, 40, 50, 60}
SetB = {50, 60, 70, 80}

print(SetA.intersection(SetB))


Output

{50, 60}


### Example: Intersection set using set and iterable as arguments

The intersection() method can take any numbers of sets or iterables to return intersection set. In the below example, the intersection() method is used with SetA, SetB and ListC to return a set containing all common elements of these three objects.

SetA = {10, 20, 30, 40, 50, 60}
SetB = {40, 50, 90}
ListC = {40, 90, 100}
print(SetA.intersection(SetB, ListC))


Output

{40}