Three numbers $$x$$, $$y$$ and $$z$$ are given and the smallest number among these three numbers can be found out using below methods.
In the below example, only if conditional statements are used.
def smallest(x, y, z):
if x <= y and x <= z:
min = x
if y <= x and y <= z:
min = y
if z <= x and z <= y:
min = z
print("Smallest number among", x,",", y,"and",z,"is: ",min)
smallest(100, 50, 25)
smallest(50, 50, 25)
Smallest number among 100 , 50 and 25 is: 25 Smallest number among 50 , 50 and 25 is: 25
It can also be solved using If-else conditional statements.
def smallest(x, y, z):
if x <= y and x <= z:
min = x
elif y <= x and y <= z:
min = y
else:
min = z
print("Smallest number among", x,",", y,"and",z,"is: ",min)
smallest(100, 50, 25)
smallest(50, 50, 25)
Smallest number among 100 , 50 and 25 is: 25 Smallest number among 50 , 50 and 25 is: 25
The above problem can also be solved using nested if-else conditional statements.
def smallest(x, y, z):
if x <= y:
if x <= z:
min = x
else:
min = z
else:
if y <= z:
min = y
else:
min = z
print("Smallest number among", x,",", y,"and",z,"is: ",min)
smallest(100, 50, 25)
smallest(50, 50, 25)
Smallest number among 100 , 50 and 25 is: 25 Smallest number among 50 , 50 and 25 is: 25
Short hand if-else conditional statements can also be used here.
def smallest(x, y, z):
min = x if x < y else y if y < z else z
print("Smallest number among", x,",", y,"and",z,"is: ",min)
smallest(100, 50, 25)
smallest(50, 50, 25)
Smallest number among 100 , 50 and 25 is: 25 Smallest number among 50 , 50 and 25 is: 25
